ccosh

接口定义

C interface：

float complex ccoshf(float complex x);

double complex ccosh(double complex x);

参数

返回值

• 返回x的双曲余弦结果y。
• 特殊值说明如下所示。

  输入值实部（x.real）	输入值虚部（x.imag）	输出值实部（y.real）	输出值虚部（y.imag）
  0.0	0.0	0.0	0.0
  0.0	-0.0	0.0	-0.0
  0.0	inf	0.0	nan
  0.0	-inf	0.0	nan
  0.0	nan	0.0	nan
  0.0	-nan	0.0	-nan
  -0.0	0.0	-0.0	0.0
  -0.0	-0.0	-0.0	-0.0
  -0.0	inf	-0.0	nan
  -0.0	-inf	-0.0	nan
  -0.0	nan	-0.0	nan
  -0.0	-nan	-0.0	-nan
  inf	0.0	inf	0.0
  inf	-0.0	inf	-0.0
  inf	inf	inf	nan
  inf	-inf	inf	nan
  inf	nan	inf	nan
  inf	-nan	inf	-nan
  -inf	0.0	-inf	0.0
  -inf	-0.0	-inf	-0.0
  -inf	inf	-inf	nan
  -inf	-inf	-inf	nan
  -inf	nan	-inf	nan
  -inf	-nan	-inf	-nan
  nan	0.0	nan	0.0
  nan	-0.0	nan	-0.0
  nan	inf	nan	nan
  nan	-inf	nan	nan
  nan	nan	nan	nan
  nan	-nan	nan	-nan
  -nan	0.0	-nan	0.0
  -nan	-0.0	-nan	-0.0
  -nan	inf	-nan	nan
  -nan	-inf	-nan	nan
  -nan	nan	-nan	nan
  -nan	-nan	-nan	-nan

依赖

C: "kc.h"

示例

    // typical usage
    double x1 = INFINITY, y1 = INFINITY;
    double x2 = 2.0, y2 = 3.0;
    double x3 = -2.5, y3 = -3.4;
    double x4 = NAN, y4 = NAN;
    double x5 = 0, y5 = 0;
    double complex z1 = ccosh(__builtin_complex(x1, y1));
    double complex z2 = ccosh(__builtin_complex(x2, y2));
    double complex z3 = ccosh(__builtin_complex(x3, y3));
    double complex z4 = ccosh(__builtin_complex(x4, y4));
    double complex z5 = ccosh(__builtin_complex(x5, y5));
    // print result
    printf("/*\n");
    printf(" * ccosh(%.2f + %.2f*I) = %.6f + %.6f*I\n", x1, y1, __real__(z1), __imag__(z1));
    printf(" * ccosh(%.2f + %.2f*I) = %.6f + %.6f*I\n", x2, y2, __real__(z2), __imag__(z2));
    printf(" * ccosh(%.2f + %.2f*I) = %.6f + %.6f*I\n", x3, y3, __real__(z3), __imag__(z3));
    printf(" * ccosh(%.2f + %.2f*I) = %.6f + %.6f*I\n", x4, y4, __real__(z4), __imag__(z4));
    printf(" * ccosh(%.2f + %.2f*I) = %.6f + %.6f*I\n", x5, y5, __real__(z5), __imag__(z5));
    printf(" **/\n");
 
   /*
    * ccosh(inf + inf*I) = inf + nan*I
    * ccosh(2.00 + 3.00*I) = -3.724546 + 0.511823*I
    * ccosh(-2.50 + -3.40*I) = -5.928686 + -1.546076*I
    * ccosh(nan + nan*I) = nan + nan*I
    * ccosh(0.00 + 0.00*I) = 1.000000 + 0.000000*I
    **/